scipy.special.bdtrc#

scipy.special.bdtrc(k, n, p, out=None) = <ufunc 'bdtrc'>#

Binomial distribution survival function.

Sum of the terms floor(k) + 1 through n of the binomial probability density,

\[\mathrm{bdtrc}(k, n, p) = \sum_{j=\lfloor k \rfloor +1}^n {{n}\choose{j}} p^j (1-p)^{n-j}\]

Parameters:

karray_like: Number of successes (double), rounded down to nearest integer.
narray_like: Number of events (int)
parray_like: Probability of success in a single event.
outndarray, optional: Optional output array for the function values

Returns:

yscalar or ndarray: Probability of floor(k) + 1 or more successes in n independent events with success probabilities of p.

See also

bdtr
betainc

Notes

The terms are not summed directly; instead the regularized incomplete beta function is employed, according to the formula,

\[\mathrm{bdtrc}(k, n, p) = I_{p}(\lfloor k \rfloor + 1, n - \lfloor k \rfloor).\]

Wrapper for the Cephes [1] routine bdtrc.

Array API Standard Support

bdtrc has experimental support for Python Array API Standard compatible backends in addition to NumPy. Please consider testing these features by setting an environment variable SCIPY_ARRAY_API=1 and providing CuPy, PyTorch, JAX, or Dask arrays as array arguments. The following combinations of backend and device (or other capability) are supported.

Library	CPU	GPU
NumPy	✅	n/a
CuPy	n/a	✅
PyTorch	✅	⛔
JAX	✅	⛔
Dask	✅	n/a

See Support for the array API standard for more information.

References

[1]

Cephes Mathematical Functions Library, https://netlib.org/cephes/

Examples

We have a coin for which the probability of showing heads when flipped is 0.525. The coin is flipped 16 times. What is the probability that the number of heads is greater than 10?

Let X be the number of heads. We want to find the probability that X > k, given k is 10, the total number of flips n is 16 and the probability p of heads in a single flip is 0.525. This is what bdtrc(k, n, p) computes:

>>> from scipy.special import bdtrc

>>> bdtrc(10, 16, 0.525)
np.float64(0.14643065267555583)

The following plot shows the graph bdtrc(k, 16, 0.525):

>>> import numpy as np
>>> import matplotlib.pyplot as plt

>>> n = 16
>>> p = 0.525
>>> k = np.arange(n + 1)
>>> plt.plot(k, bdtrc(k, n, p), 'o')
>>> plt.grid(True)
>>> plt.xlabel('k')
>>> plt.title(f"bdtrc(k, {n}, {p})")
>>> plt.show()