Log Double Exponential (Log-Laplace) Distribution# One shape parameter c>0. The support is x≥0. f(x;c)={c2xc−10<x<1c2x−c−1x≥1F(x;c)={12xc0<x<11−12x−cx≥1G(q;c)={(2q)1/c0≤q<12(2−2q)−1/c12≤q≤1 h[X]=log(2ec) Implementation: scipy.stats.loglaplace