# scipy.signal.impulse2¶

scipy.signal.impulse2(system, X0=None, T=None, N=None, **kwargs)[source]

Impulse response of a single-input, continuous-time linear system.

Parameters
systeman instance of the LTI class or a tuple of array_like

describing the system. The following gives the number of elements in the tuple and the interpretation:

• 1 (instance of lti)

• 2 (num, den)

• 3 (zeros, poles, gain)

• 4 (A, B, C, D)

X01-D array_like, optional

The initial condition of the state vector. Default: 0 (the zero vector).

T1-D array_like, optional

The time steps at which the input is defined and at which the output is desired. If T is not given, the function will generate a set of time samples automatically.

Nint, optional

Number of time points to compute. Default: 100.

kwargsvarious types

Additional keyword arguments are passed on to the function scipy.signal.lsim2, which in turn passes them on to scipy.integrate.odeint; see the latter’s documentation for information about these arguments.

Returns
Tndarray

The time values for the output.

youtndarray

The output response of the system.

Notes

The solution is generated by calling scipy.signal.lsim2, which uses the differential equation solver scipy.integrate.odeint.

If (num, den) is passed in for system, coefficients for both the numerator and denominator should be specified in descending exponent order (e.g. s^2 + 3s + 5 would be represented as [1, 3, 5]).

New in version 0.8.0.

Examples

Compute the impulse response of a second order system with a repeated root: x''(t) + 2*x'(t) + x(t) = u(t)

>>> from scipy import signal
>>> system = ([1.0], [1.0, 2.0, 1.0])
>>> t, y = signal.impulse2(system)
>>> import matplotlib.pyplot as plt
>>> plt.plot(t, y) #### Previous topic

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