scipy.interpolate.UnivariateSpline¶

class
scipy.interpolate.
UnivariateSpline
(x, y, w=None, bbox=[None, None], k=3, s=None, ext=0, check_finite=False)[source]¶ 1D smoothing spline fit to a given set of data points.
Fits a spline y = spl(x) of degree k to the provided x, y data. s specifies the number of knots by specifying a smoothing condition.
 Parameters
 x(N,) array_like
1D array of independent input data. Must be increasing; must be strictly increasing if s is 0.
 y(N,) array_like
1D array of dependent input data, of the same length as x.
 w(N,) array_like, optional
Weights for spline fitting. Must be positive. If None (default), weights are all equal.
 bbox(2,) array_like, optional
2sequence specifying the boundary of the approximation interval. If None (default),
bbox=[x[0], x[1]]
. kint, optional
Degree of the smoothing spline. Must be 1 <= k <= 5. Default is k = 3, a cubic spline.
 sfloat or None, optional
Positive smoothing factor used to choose the number of knots. Number of knots will be increased until the smoothing condition is satisfied:
sum((w[i] * (y[i]spl(x[i])))**2, axis=0) <= s
If None (default),
s = len(w)
which should be a good value if1/w[i]
is an estimate of the standard deviation ofy[i]
. If 0, spline will interpolate through all data points. extint or str, optional
Controls the extrapolation mode for elements not in the interval defined by the knot sequence.
if ext=0 or ‘extrapolate’, return the extrapolated value.
if ext=1 or ‘zeros’, return 0
if ext=2 or ‘raise’, raise a ValueError
if ext=3 of ‘const’, return the boundary value.
The default value is 0.
 check_finitebool, optional
Whether to check that the input arrays contain only finite numbers. Disabling may give a performance gain, but may result in problems (crashes, nontermination or nonsensical results) if the inputs do contain infinities or NaNs. Default is False.
See also
BivariateSpline
a base class for bivariate splines.
SmoothBivariateSpline
a smoothing bivariate spline through the given points
LSQBivariateSpline
a bivariate spline using weighted leastsquares fitting
RectSphereBivariateSpline
a bivariate spline over a rectangular mesh on a sphere
SmoothSphereBivariateSpline
a smoothing bivariate spline in spherical coordinates
LSQSphereBivariateSpline
a bivariate spline in spherical coordinates using weighted leastsquares fitting
RectBivariateSpline
a bivariate spline over a rectangular mesh
InterpolatedUnivariateSpline
a interpolating univariate spline for a given set of data points.
bisplrep
a function to find a bivariate Bspline representation of a surface
bisplev
a function to evaluate a bivariate Bspline and its derivatives
splrep
a function to find the Bspline representation of a 1D curve
splev
a function to evaluate a Bspline or its derivatives
sproot
a function to find the roots of a cubic Bspline
splint
a function to evaluate the definite integral of a Bspline between two given points
spalde
a function to evaluate all derivatives of a Bspline
Notes
The number of data points must be larger than the spline degree k.
NaN handling: If the input arrays contain
nan
values, the result is not useful, since the underlying spline fitting routines cannot deal withnan
. A workaround is to use zero weights for notanumber data points:>>> from scipy.interpolate import UnivariateSpline >>> x, y = np.array([1, 2, 3, 4]), np.array([1, np.nan, 3, 4]) >>> w = np.isnan(y) >>> y[w] = 0. >>> spl = UnivariateSpline(x, y, w=~w)
Notice the need to replace a
nan
by a numerical value (precise value does not matter as long as the corresponding weight is zero.)Examples
>>> import matplotlib.pyplot as plt >>> from scipy.interpolate import UnivariateSpline >>> x = np.linspace(3, 3, 50) >>> y = np.exp(x**2) + 0.1 * np.random.randn(50) >>> plt.plot(x, y, 'ro', ms=5)
Use the default value for the smoothing parameter:
>>> spl = UnivariateSpline(x, y) >>> xs = np.linspace(3, 3, 1000) >>> plt.plot(xs, spl(xs), 'g', lw=3)
Manually change the amount of smoothing:
>>> spl.set_smoothing_factor(0.5) >>> plt.plot(xs, spl(xs), 'b', lw=3) >>> plt.show()
Methods
__call__
(x[, nu, ext])Evaluate spline (or its nuth derivative) at positions x.
antiderivative
([n])Construct a new spline representing the antiderivative of this spline.
derivative
([n])Construct a new spline representing the derivative of this spline.
derivatives
(x)Return all derivatives of the spline at the point x.
Return spline coefficients.
Return positions of interior knots of the spline.
Return weighted sum of squared residuals of the spline approximation.
integral
(a, b)Return definite integral of the spline between two given points.
roots
()Return the zeros of the spline.
Continue spline computation with the given smoothing factor s and with the knots found at the last call.
validate_input