scipy.stats.Mixture.

median#

Mixture.median(*, method=None)[source]#

Median (50th percentil)

If a continuous random variable \(X\) has probability \(0.5\) of taking on a value less than \(m\), then \(m\) is the median. That is, the median is the value \(m\) for which:

\[P(X ≤ m) = 0.5 = P(X ≥ m)\]
Parameters:
method{None, ‘formula’, ‘icdf’}

The strategy used to evaluate the median. By default (None), the infrastructure chooses between the following options, listed in order of precedence.

  • 'formula': use a formula for the median

  • 'icdf': evaluate the inverse CDF of 0.5

Not all method options are available for all distributions. If the selected method is not available, a NotImplementedError will be raised.

Returns:
outarray

The median

See also

mean
mode
icdf

References

Examples

Instantiate a distribution with the desired parameters:

>>> from scipy import stats
>>> X = stats.Uniform(a=0., b=10.)

Compute the median:

>>> X.median()
5
>>> X.median() == X.icdf(0.5) == X.iccdf(0.5)
True
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