SciPy

scipy.stats.mstats.count_tied_groups

scipy.stats.mstats.count_tied_groups(x, use_missing=False)[source]

Counts the number of tied values.

Parameters:
x : sequence

Sequence of data on which to counts the ties

use_missing : bool, optional

Whether to consider missing values as tied.

Returns:
count_tied_groups : dict

Returns a dictionary (nb of ties: nb of groups).

Examples

>>> from scipy.stats import mstats
>>> z = [0, 0, 0, 2, 2, 2, 3, 3, 4, 5, 6]
>>> mstats.count_tied_groups(z)
{2: 1, 3: 2}

In the above example, the ties were 0 (3x), 2 (3x) and 3 (2x).

>>> z = np.ma.array([0, 0, 1, 2, 2, 2, 3, 3, 4, 5, 6])
>>> mstats.count_tied_groups(z)
{2: 2, 3: 1}
>>> z[[1,-1]] = np.ma.masked
>>> mstats.count_tied_groups(z, use_missing=True)
{2: 2, 3: 1}

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