scipy.optimize.leastsq¶

scipy.optimize.
leastsq
(func, x0, args=(), Dfun=None, full_output=0, col_deriv=0, ftol=1.49012e08, xtol=1.49012e08, gtol=0.0, maxfev=0, epsfcn=None, factor=100, diag=None)[source]¶ Minimize the sum of squares of a set of equations.
x = arg min(sum(func(y)**2,axis=0)) y
 Parameters
 funccallable
Should take at least one (possibly length N vector) argument and returns M floating point numbers. It must not return NaNs or fitting might fail.
 x0ndarray
The starting estimate for the minimization.
 argstuple, optional
Any extra arguments to func are placed in this tuple.
 Dfuncallable, optional
A function or method to compute the Jacobian of func with derivatives across the rows. If this is None, the Jacobian will be estimated.
 full_outputbool, optional
nonzero to return all optional outputs.
 col_derivbool, optional
nonzero to specify that the Jacobian function computes derivatives down the columns (faster, because there is no transpose operation).
 ftolfloat, optional
Relative error desired in the sum of squares.
 xtolfloat, optional
Relative error desired in the approximate solution.
 gtolfloat, optional
Orthogonality desired between the function vector and the columns of the Jacobian.
 maxfevint, optional
The maximum number of calls to the function. If Dfun is provided, then the default maxfev is 100*(N+1) where N is the number of elements in x0, otherwise the default maxfev is 200*(N+1).
 epsfcnfloat, optional
A variable used in determining a suitable step length for the forward difference approximation of the Jacobian (for Dfun=None). Normally the actual step length will be sqrt(epsfcn)*x If epsfcn is less than the machine precision, it is assumed that the relative errors are of the order of the machine precision.
 factorfloat, optional
A parameter determining the initial step bound (
factor *  diag * x
). Should be in interval(0.1, 100)
. diagsequence, optional
N positive entries that serve as a scale factors for the variables.
 Returns
 xndarray
The solution (or the result of the last iteration for an unsuccessful call).
 cov_xndarray
The inverse of the Hessian. fjac and ipvt are used to construct an estimate of the Hessian. A value of None indicates a singular matrix, which means the curvature in parameters x is numerically flat. To obtain the covariance matrix of the parameters x, cov_x must be multiplied by the variance of the residuals – see curve_fit.
 infodictdict
a dictionary of optional outputs with the keys:
nfev
The number of function calls
fvec
The function evaluated at the output
fjac
A permutation of the R matrix of a QR factorization of the final approximate Jacobian matrix, stored column wise. Together with ipvt, the covariance of the estimate can be approximated.
ipvt
An integer array of length N which defines a permutation matrix, p, such that fjac*p = q*r, where r is upper triangular with diagonal elements of nonincreasing magnitude. Column j of p is column ipvt(j) of the identity matrix.
qtf
The vector (transpose(q) * fvec).
 mesgstr
A string message giving information about the cause of failure.
 ierint
An integer flag. If it is equal to 1, 2, 3 or 4, the solution was found. Otherwise, the solution was not found. In either case, the optional output variable ‘mesg’ gives more information.
See also
least_squares
Newer interface to solve nonlinear leastsquares problems with bounds on the variables. See
method=='lm'
in particular.
Notes
“leastsq” is a wrapper around MINPACK’s lmdif and lmder algorithms.
cov_x is a Jacobian approximation to the Hessian of the least squares objective function. This approximation assumes that the objective function is based on the difference between some observed target data (ydata) and a (nonlinear) function of the parameters f(xdata, params)
func(params) = ydata  f(xdata, params)
so that the objective function is
min sum((ydata  f(xdata, params))**2, axis=0) params
The solution, x, is always a 1D array, regardless of the shape of x0, or whether x0 is a scalar.
Examples
>>> from scipy.optimize import leastsq >>> def func(x): ... return 2*(x3)**2+1 >>> leastsq(func, 0) (array([2.99999999]), 1)