scipy.fftpack.rfft(x, n=None, axis=-1, overwrite_x=False)[source]

Discrete Fourier transform of a real sequence.


x : array_like, real-valued

The data to transform.

n : int, optional

Defines the length of the Fourier transform. If n is not specified (the default) then n = x.shape[axis]. If n < x.shape[axis], x is truncated, if n > x.shape[axis], x is zero-padded.

axis : int, optional

The axis along which the transform is applied. The default is the last axis.

overwrite_x : bool, optional

If set to true, the contents of x can be overwritten. Default is False.


z : real ndarray

The returned real array contains:

[y(0),Re(y(1)),Im(y(1)),...,Re(y(n/2))]              if n is even
[y(0),Re(y(1)),Im(y(1)),...,Re(y(n/2)),Im(y(n/2))]   if n is odd


y(j) = sum[k=0..n-1] x[k] * exp(-sqrt(-1)*j*k*2*pi/n)
j = 0..n-1

See also

fft, irfft, numpy.fft.rfft


Within numerical accuracy, y == rfft(irfft(y)).

Both single and double precision routines are implemented. Half precision inputs will be converted to single precision. Non floating-point inputs will be converted to double precision. Long-double precision inputs are not supported.

To get an output with a complex datatype, consider using the related function numpy.fft.rfft.


>>> from scipy.fftpack import fft, rfft
>>> a = [9, -9, 1, 3]
>>> fft(a)
array([  4. +0.j,   8.+12.j,  16. +0.j,   8.-12.j])
>>> rfft(a)
array([  4.,   8.,  12.,  16.])

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